151-xxx Programming Mechanical Engineer
โดย ผศ.สราวุฎฐ์ วรสุมันต์ , ประยุทธ พันธุลาภHeat Transfer
Thermal conductivity of some selected gases, insulation products, aluminum, asphalt, brass, copper, steel and other common materialsViscosity of Water
Viscosity of WaterAdvance Topics
Numerical solutions with GNU OCTAVEOctave and C compiler on-line
Click here to run -> rextester.comLoop Flow Chart
ข้อสอบ กว
- ข้อสอบ กว ทุกวิชา [/] Check ยอมรับเงื่อนไข
- Computer Programming
- Engineering Mechanic Static/Dynamic
- Engineering Drawing
- Engineering Materials
%Example 1 t = 0:0.1:6.3; plot (t, cos(t), "-;cos(t);", t, sin(t*0.5), "-b;sin(t);"); print -dpng some_name.png; %Example 2 x=1:0.1:10; plot(x, sin(x)); print -dpng some_name.png; %Example 3 A = [3,12; 4,2;] C = [15; 6;] x = inv(A)*C %Example 4 Hydro static rho = 1000 %kg/cu.m. g = 9.81 %m/s2 h = 20 %m p = rho * g * h %N/sq.m
ข้อสอบ กว
- ข้อสอบ กว ทุกวิชา [/] Check ยอมรับเงื่อนไข
- Computer Programming
- Engineering Mechanic Static/Dynamic
- Engineering Drawing
- Engineering Materials
Example 05
%*****Reaction at simple beam printf("Student No.2\n") printf("**************\n") F1 = 150 %KN L = 6 %m L1 = 1 %m L2 = L - L1 A = [1,1; L, 0;] F = [F1; (L2*F1);] R = inv(A)*F printf("R1 = %6.3f\n",R(1)) printf("R2 = %6.3f\n",R(2))
Example 06
%****Cantiliver Beam printf("Student No.1\n") printf("**************\n") F1 = 300 %KN L = 2 %m A = [1,0; 0, 1;] F = [F1; (L*F1);] R = inv(A)*F printf("RY = %6.3f KN\n",R(1)) printf("MA = %6.3f KN.m\n",R(2))Example 07 -->
%*****Reaction at simple beam F1 F2 printf("Student No.2\n") printf("**************\n") F1 = 100 %KN F2 = 50 %KN L = 6 %m L1 = 1 %m L2 = 1.2 %m FT = F1 + F2 %total force MT = (L1*F1) + ((L1+L2)*F2) %total moment A = [1,1; 0, L;] F = [FT; MT;] R = inv(A)*F printf("R1 = %6.3f\n",R(1)) printf("R2 = %6.3f\n",R(2))Example 08
%*****Reaction at Cantilever Beam F1 F2 printf("Student No.2\n") printf("**************\n") F1 = 100 %KN F2 = 50 %KN L = 6 %m L1 = 1 %m FT = F1 + F2 %total force MT = (L*F1) + (L1*F2) %total moment A = [1,0; 0,1;] F = [FT; MT;] R = inv(A)*F printf("RY = %6.3f\n",R(1)) printf("MA = %6.3f\n",R(2))Example 09
%****Ex 9. Solve Matrix
printf("Student No.2\n") printf("**************\n") printf("**Solve Matrix***\n") printf("**************\n") A = [ -4, -11, 5, -5; -11, -8, 10, -9; -5, -5, 8, -7; -2, -3, 8, -4; ] F = [ -165; -258; -149; -69; ] disp "***********************" R = inv(A)*F printf("a = %6.3f \n",R(1)) printf("b = %6.3f \n",R(2)) printf("c = %6.3f \n",R(3)) printf("d = %6.3f \n",R(4))
#include <stdio.h> int main() { int number; printf("Enter an integer: "); // reads and stores input scanf("%d", &number); // displays output printf("You entered: %d", number); return 0; }
- -โครงสร้างของคอมพิวเตอร์ ->Link
- -ประวัติความเป็นมาของคอมพิวเตอร์ ->Link1| ->Link2
- -หลักการทำงานเบื้องต้นของระบบคอมพิวเตอร์ ->Link
-
->Bill Gates
->Link2
พื้นฐานการเขียนโปรแกรมคอมพิวเตอร์
(Programming Fundamentals)
การเขียนโปรแกรมคอมพิวเตอร์ C
Link->ข้อสอบ Computer Programminghttps://www.onlinegdb.com/online_c_compiler
*****Open C Online********C Examples***
Android Text Editor for Copy/Paste codes
Link-> Play Store Editor
C Keywords
***Link->C Keywords***ความแตกต่างระหว่าง Error กับ Warning
- Error
- >Link->First BUG
- Warning
การใช้ Comment
// นำหน้า หมายถึง compiler จะไม่สนใจตั้งแต่ // จนสิ้นสุดบรรทัดนั้น
/* */ คลุม หมายถึง compiler จะไม่สนใจตั้งแต่ /* จนถึง */
Link->Data Types |
Link->C-input-output
Link->C-String
/* Example 1 */ #include <stdio.h> int main() { printf ("Hello world!"); return 0; } /* Example 2 */ #include <stdio.h> int main() { int number; printf("Enter an integer: "); // reads and stores input scanf("%d", &number); // displays output printf("You entered: %d", number); return 0; }
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เอกสารประกอบการสอน if else, while, do while
*****Link->PDF*****
Relational Operator
Home Work#2
#include <stdio.h> #include <string.h> int main() { int i, found = 0; char size[6]; //inch char sv[20]; float dia = 0; //m. float r = 0; //m. float flow = 0; //cu.m./s float v = 2; // m/s char pipe_size[5][20] = { "1","2","3","4","6" }, name[10]; char pipe_diam[5][20] = { "28.0","51.4", "76.2", "97.8", "141.6" }, data[10]; printf("Enter Size [inch]: "); scanf("%s",size); printf("Enter Velocity [m/s]: "); scanf("%s",sv); for(i = 0; i < 5; i++) { if(strcmp(size, pipe_size[i]) == 0 ) { found = 1; //printf("data = %s" ,pipe_diam[i] ); sscanf(pipe_diam[i] , "%f", &dia); //convert string to float sscanf(sv , "%f", &v); //convert string to float r = (dia * 0.5) / 1000.0; //mm flow = v * (3.14159 * r * r) * 1000; //liter/s printf("flow [liter/s] = %f" , flow); break; //out of for loop } } return 0; }
Home Work#1
#include <stdio.h> int main() { int cpucore = 8; int camera = 3; int ram = 64; if (camera<2) { printf("Camera NOT Pass\n"); } else { printf("Camera Pass\n"); } if (cpucore>4) { printf("CPU CORE Pass\n"); } else { printf("CPU CORE NOT pass\n"); } if (ram>32) { printf("RAM Pass\n"); } else { printf("RAM NOT pass\n"); } return 0; }
การใช้ if else
//***Example if 1*** #include <stdio.h> int main() { int x = 20; int y = 22; if (x<y) { printf("Variable x is less than y"); } return 0; } //***Example if else*** #include <stdio.h> int main() { int x = 20; int y = 22; if (x<y) { printf("Variable x is less than y"); } else { printf("Variable x is NOT less than y"); } return 0; }
การใช้ for loop
#include <stdio.h> int main() { int age = 18; int height = 155; int weight = 42; if (height<=150) { printf("height NOT Pass\n"); } else { printf("height Pass\n"); } if (age<=20) { printf("age Pass\n"); } else { printf("age NOT pass\n"); } if (weight<=80) { printf("weight Pass\n"); } else { printf("weight NOT pass\n"); } return 0; }
//***Example Loop 1*** #include <stdio.h> int main () { int a; int b; b = 1; /* for loop execution */ for( a = 5; a > 0; a = a - 1 ){ b = b + 2; printf("value of a: %d b: %d\n ", a ,b); //printf("value of b: %d\n", b); } return 0; } //***Example for loop sum*** #include <stdio.h> int main() { int i; int sum; sum = 0; for (i=1; i<=3; i++) { sum = sum + i; printf("%d\n", sum); } return 0; } //***Example for loop average*** #include <stdio.h> int main() { int i; float sum; float avg; sum = 0; for (i=1; i<=6; i++) { sum = sum + i; printf("i=%d , sum=%f\n", i,sum); } printf("i=%d \n",i); //reduce i by 1 i = i - 1; printf("***i=%d*** \n",i); avg = sum / (float)i; printf("%6.3f\n", avg); return 0; } //***Example for loop array*** #include <stdio.h> int main () { int n[4][4]; /* n is an array of 3X3 integers */ int i,j; for ( i = 0; i < 4; i++ ) { for ( j = 0; j < 4; j++ ) { n[j][i] = i; /* set element at location n[j][i] = i */ printf("n[%d][%d] = %d\n", i,j,n[j][i]); } } return 0; }
การใช้ while loop
//***Example While Loop 1*** #include <stdio.h> int main() { int count=1; while (count <= 4) { printf("%d ", count); count++; } return 0; } //***Example While Loop 2*** #include <stdio.h> int main() { int x; int y; x = 5; y = 2; while (x > 0) { x = x - 1; y = y * x; printf("y = %d \n ", y); } return 0; } //***Example While Loop 3*** #include <stdio.h> int main() { int i; int j; i = 1; j = 0; for ( i = 1; i <= 4; i++ ) { if ((i-1)/2 == 0) { printf("i = %d \n ", i); j = i +1; } } return 0; }
การใช้ do while loop
//***Example Do While Loop 1*** #include <stdio.h> int main() { int j=0; do { printf("Value of variable j is: %d\n", j); j++; }while (j<=3); return 0; }
/* Example 3.1 */ #include <stdio.h> int main() { short a; long b; long long c; long double d; printf("size of short = %d bytes\n", sizeof(a)); printf("size of long = %d bytes\n", sizeof(b)); printf("size of long long = %d bytes\n", sizeof(c)); printf("size of long double= %d bytes\n", sizeof(d)); return 0; } /* Example 3.2 */ #include <stdio.h> int main() { short a; long b; long long c; long double d; printf("size of short = %d bytes\n", (int)sizeof(a)); printf("size of long = %d bytes\n", (int)sizeof(b)); printf("size of long long = %d bytes\n", (int)sizeof(c)); printf("size of long double= %d bytes\n", (int)sizeof(d)); return 0; } /* Example 4 */ #include <stdio.h> int main(){ char chr = 'a'; printf("character = %c.", chr); return 0; } /* Example 5 */ #include <stdio.h> int main() { char first[100], last[100]; int i; printf("nEnter your first name:"); scanf("%s", first ); printf("nEnter your last name:"); scanf("%s", last ); printf("nYour full name is: %s %sn", first, last ); printf("First name is: "); for( i=0; i<100; i++ ){ if ((first[i] > 32) && (first[i] < 123)){ printf("%c ",first[i]); } } printf("nLast name is: "); for( i=0; i<100; i++ ){ printf("%c ",last[i]); } printf("n"); return 0; }
การเขียนโปรแกรมคอมพิวเตอร์ Octave
https://octave-online.net/
*****Open Octave Online*****Octave แก้ระบบสมการ
ระบบสมการ ->Link1A = [1,1,1; 0,2,5; 2,5,-1;] C = [6;-4;27;] x = inv(A) * C x
Introduction to Octave
# i = 2 * 4 i # x = 0 : 0.1 : 1; x y = [ 0 : 0.1 : 1]; y #แก้ระบบสมการ A = [1,1,1; 0,2,5; 2,5,-1;] C = [6;-4;27;] x = inv(A) * C x ######plot1############### x = 1:5; y = 1:5; plot (x,y,"g"); title ("plot() of green line at 45 degrees"); ######plot2############### x = 1:5; y = 1:5; plot (x,y,"g*"); title ("plot() of green stars along a line at 45 degrees"); ###### plot function 1 ######### x = -10:0.1:10; plot (x, sin (x)); ###### plot function 2 ######### x = -10:0.1:10; y = sin(x); plot (x, y); ###### plot function 3 ######### x1 = 1:5; y1 = 1:5; x2 = 5:9; y2 = 5:-1:1; plot (x1,y1,"bo-", x2,y2,"rs-"); axis ("tight"); title ({"plot() of blue circles ascending and red squares descending"; "connecting lines drawn"}); ###### plot function 4 ######### x = [0:10]'; y = [sin(x), cos(x)] h = stem (x, y); set (h(2), "color", "g"); set (h(1), "basevalue", -1) ###### Histogram 1 ######### hist (randn (10000, 1), 30); ###### Histogram 2 ######### h = bar (rand (5, 10)); set (h(1), "basevalue", 0.5); ###### Histogram 3 ######### h = bar (rand (10, 3)); set (h(1), "facecolor", "r") set (h(2), "facecolor", "g") set (h(3), "facecolor", "b") ###### Rose Map ######### [th, r] = rose ([2*randn(1e5,1), pi + 2*randn(1e5,1)]); polar (th, r); ###### Contour 1 ######### x = 0:2; y = x; z = x' * y; contour (x, y, z, 2:3) ###### Contour 2 ######### [x, y, z] = peaks (50); contourf (x, y, z, -7:9)
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Sheet
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<.p>
แก้ระบบสมการ
->Link1A = [1,1,1; 0,2,5; 2,5,-1;] C = [6;-4;27;] x = inv(A) * C x
Assignment 1/2019
***เลยกำหนดส่ง 5 ม.ค. 2563***